Discussion Forum : Vector Algebra
Question -


If the points A,B and C have position vectors (2,1,1), (6,-1,2) and (14,-5,P) respectively and if they are collinear, then P =

Options:
A .   2
B .   4
C .   6
D .   8
Answer: Option B
:
B

OA=2^i+^j+^k,OB=6^i^j+2^k,OC=14^i5^j+P^kAB=OBOA=4^i2^j+^k,AC=OCOA=12^i6^j+(p1)^k
A, B, C are collinear AC=λAB12^i6^j+(p1)^k=λ(4^i2^j+^k)
λ=3,p1=3p=4.
 



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