Discussion Forum : Application Of Derivatives
Question -


A function f such that f(a)=f′′(a)=......f2n(a)=0 and f has a local maximum value b at x = a, if f (x) is

Options:
A .   (xa)2n+2
B .   b1(x+1a)2n+1
C .   b(xa)2n+2
D .   (xa)2n+2b.
Answer: Option C
:
C

For local maximum or local minimum odd derivative must be equal to zero.
For local maxima, even derivative must be negative.               
Since maximum value at x = a is b.

f(x)=b(xa)2n+2(f2n+2(a)=ve)
Hence (c) is the correct answer.



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