Discussion Forum : Application Of Derivatives
Question -
The two curves x3−3xy2+2=0 and 3x2y−y3−2=0
Answer: Option A
:
A
x3−3xy2+2=0...(1)3x2y−y3−2=0...(2)
On differentiating equations (1) and (2) w.r.t x, we obtain
(dydx)c1=x2−y22xy and (dydx)c2=−2xyx2−y2
Since m1.m2=−1.Therefore the two curves cut at right angles.
Hence (a) is the correct answer.
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:
A
x3−3xy2+2=0...(1)3x2y−y3−2=0...(2)
On differentiating equations (1) and (2) w.r.t x, we obtain
(dydx)c1=x2−y22xy and (dydx)c2=−2xyx2−y2
Since m1.m2=−1.Therefore the two curves cut at right angles.
Hence (a) is the correct answer.
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