The order of the differential equation of all tangent lines to the parabola y=x2 is
Options:
A .  
1
B .  
2
C .  
3
D .  
4
Answer: Option A : A The parametric form of the given equation is x=t,y=t2.The equation of any tangent at t is 2xt=y+t2, Differentiating we get 2t=y1(=dydx) putting this value in the above equation, we have 2xy12=y+(y12)2⇒4xy1=4y+y21 The order of this equation is 1 Hence (A) is the correct answer
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