Velocity constant of a reaction at 290 K was found to 3.2×10−3sec&

Question -

Velocity constant of a reaction at 290 K was found to $3.2 \times 10^{- 3} s e c^{- 1}$ . When the temperature is raised to 310 K, it will be about:

Options:

A .

6.4 \times 10^{- 3}

B .

3.2 \times 10^{- 4}

C .

9.6 \times 10^{- 3}

D .

1.28 \times 10^{- 2}

Answer: Option D
:
D
From the Arhenius eqn, we know that the rate of a reaction doubles for every 10 K rise in temperature.

\frac{k_{2}}{k_{1}} = 2^{2} \Rightarrow k_{2} = 3.2 \times 10^{- 3} \times 4 = 1.28 \times 10^{- 2} s e c^{- 1}

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