10−4 g of gelatin is required to be added to 100 cm3 of a stanadar

Discussion Forum : Surface Chemistry

Question -

$10^{- 4}$ g of gelatin is required to be added to 100 $c m^{3}$ of a stanadard gold solution to just prevent its precipitation by addition of 1 $c m^{3}$ of 10% NaCl solution to it. Hence, gold number of gelatin is?

Options:

A . 10

B . 1

C . 0.1

D . 0.01

Answer: Option D
:
D

$10^{- 4} g = 0.1 m g$
$100 c m^{3}$ of gold sol require 0.1 mg
$∴ 10 c m^{3}$ of gold sol will required 0.01 mg
Hence, gold number = 0.01.

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