How many grams of oxygen are required for complete combustion of 2 moles of be

Question -

How many grams of oxygen are required for complete combustion of 2 moles of benzene?

Options:

A . 450g

B . 480g

C . 500g

D . 530g

Answer: Option B
:
B

The balanced reaction for combustion of benzene is

$2 C_{6} H_{6} + 15 O_{2} \to$ $12 C O_{2} + 6 H_{2} O$

Therefore, 15 moles of oxygen gas is required for complete combustion of benzene.

We know that, $1 m o l e$ of $O_{2}$ = $32 g$

$∴$ $15 m o l e s$ of $O_{2}$ = $15 \times 32$ = $480 g$

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