Calculate Molarity of a solution having 3.42 gm sucrose in 500 mL

Question -

Calculate Molarity of a solution having 3.42 gm sucrose in 500 mL - solution.

Options:

A . 0.2 M

B . 0.02 M

C . 2 M

D . 0.342 M

Answer: Option B
:
B
We know that,
Molarity=

\frac{No. of moles of solute}{No of litres of solution}

We know the given weight of sucrose from which the number of moles of sucrose can be calculated. Therefore No. of moles =

\frac{G i v e n w e i g h t}{M o l e c u l a r w e i g h t}

(solute is sucrose)

= \frac{3.42}{342} = 0.01

When 0.01 moles of sucrose is added to 500ml

\Rightarrow M o l a r i t y = 0.01 \times \frac{1}{500 \times 10^{- 3}} (1 m L = 10^{- 3} L)

\Rightarrow

Molarity = 0.02 M

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