Calculate the volume of CO2 evolved at NTP when 20g of CaCO3 is heated strongly.
The question gives weight of reactants and asks the volume of product. So, it is a weight-volume problem. Start by balancing the reaction
CaCO3 → CaO + CO2(g) ↑
∴ 1 mole of CaCO3 gives 1 mole of CO2
From Avagadro's Law, 1 mole of CO2 at NTP occupies 22.4L
∴ 1 mole of CaCO3 = 22.4 L of CO2
100g = 22.4L of CO2
∴ 20g = 20 × 22.4100 = 4.48 L of CO2
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