The de-Brogile wavelength of an electron moving in a circular orbit is λ

Question -

The de-Brogile wavelength of an electron moving in a circular orbit is $λ$ . The minimum radius of orbit is

Options:

A .

\frac{λ}{π}

B .

\frac{λ}{2 π}

C .

\frac{λ}{4 π}

D .

\frac{λ}{3 π}

Answer: Option B
:
B

We know $2 π r = n λ$

From minimum radius $n = 1$

$2 π r_{m i n} = λ$

$r_{m i n} = \frac{λ}{2 π}$

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