Discussion Forum : Motion In One Dimension
Question -


The initial velocity of a particle is 10 m/sec and its retardation is 2 m/sec2. The distance moved by the particle in 5th second of its motion is  

Options:
A .   1 m
B .   19 m
C .   50 m
D .   75 m
Answer: Option A
:
A

Using the formula for the distance travelled in the nth second


Sn=ua2(2n1)=1022(2×51)=1meter



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