The initial velocity of a particle is 10 m/sec and its retardation is 2 m/sec2. The distance moved by the particle in 5th second of its motion is
Using the formula for the distance travelled in the nth second
Sn=u−a2(2n−1)=10−22(2×5−1)=1meter
Your email address will not be published. Required fields are marked *
Submit Your Solution hear: