An amplitude modulated wave is modulated to 50%. What is the saving in power i

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An amplitude modulated wave is modulated to 50%. What is the saving in power if carrier as well as one of the side bands are suppressed

Answer: Option C
:
C

$P_{s b}$ = $P_{c} (\frac{m_{a}}{2})^{2}$ = $P_{c} \frac{({0.5}^{2})}{4} = 0.0625 P_{c}$
Also P = $P_{c} (1 + \frac{{m_{a}}^{2}}{2}) = P_{c} (1 + \frac{{(0.5)}^{2}}{2}) = 1.125 P_{c}$
$∴$ % saving = $\frac{(1.125 P_{c} - 0.0625 P_{c})}{1.125 P_{c}} \times 100$ = 94.4%

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