A frictionless wire AB is fixed on a circular frame of radius R. A very small s

Discussion Forum : Motion In One Dimension

Question -

A frictionless wire AB is fixed on a circular frame of radius R. A very small spherical ball slips on this wire. The time taken by this ball to slip from A to B is

Options:

A .

\frac{2 \sqrt{g R}}{g c o s θ}

B .

\frac{2 \sqrt{g R} c o s θ}{g}

C .

2 \sqrt{\frac{R}{g}}

D .

\frac{g R}{\sqrt{g c o s θ}}

Answer: Option C
:
C

$∠ A B C = 90^{0} Acceleration along AB is a = g c o s θ Distance travelled is A B = 2 R C o s θ We have 2 R C o s θ = \frac{1}{2} \times g c o s θ t^{2} \Rightarrow t = 2 \sqrt{\frac{R}{g}}$

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