A mass m slips along a smooth hemispherical surface of radius R starting from

Question -

A mass m slips along a smooth hemispherical surface of radius R starting from rest at the top as shown.

The velocity of the mass at the bottom of the surface is

Options:

A .

\sqrt{R g}

B .

\sqrt{2 R g}

C .

2 \sqrt{π R g}

D .

2 \sqrt{π R g}

Answer: Option B
:
B

By applying law of conservation of energy

mgR = $\frac{1}{2} m v^{2}$

$\Rightarrow v = \sqrt{2 R g}$

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