A lorry and a car moving with the same K.E. are brought to rest by applying the same retarding force, then Options: A . &nbsp Lorry will come to rest in a shorter distance B . &nbsp Car will come to rest in a shorter distance C . &nbsp Both come to rest in a same distance D . &nbsp None of the above

A lorry and a car moving with the same K.E. are brought to rest by applying&#x

Question -

A lorry and a car moving with the same K.E. are brought to rest by applying the same retarding force, then

Options:

A . Lorry will come to rest in a shorter distance

B . Car will come to rest in a shorter distance

C . Both come to rest in a same distance

D . None of the above

Answer: Option C
:
C

Stopping distance = $\frac{k i n e t i c e n e r g y}{r e t a r d i n g f o r c e} \Rightarrow s = \frac{1}{2} \frac{m u^{2}}{F}$

If lorry and car both possess same kinetic energy and retarding force is also equal then both come to rest in the same distance.

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