| → A | = 4 u n i t s | → B | = 10 u n i t s If angle between → A & → B is 60 ∘ then find → A . → B . Options: A . &nbsp 20 B . &nbsp 40 C . &nbsp 0 D . &nbsp 20 √ 3

Answer: Option A : A → A . → B = | A | | B | c o s 60 ∘ . | ¯ ¯¯ ¯ A | = 4 ; | ¯ ¯¯ ¯ B | = 10 = 4 × 10 × 1 2 Scalar product of → A & → B = 20

|→A|=4 units |→B|=10 units If angle between

Question -

$| \to A | = 4 u n i t s$

$| \to B | = 10 u n i t s$ If angle between $\to A$ & $\to B$ is $60^{\circ}$ then find $\to A$ . $\to B$ .

Options:

A .

20

B .

40

C .

0

D .

20 \sqrt{3}

Answer: Option A
:
A

$\to A$ . $\to B$ = $| A | | B | c o s 60^{\circ}$ .

$| ¯ ¯¯ ¯ A | = 4$ ; $| ¯ ¯¯ ¯ B | = 10$

= $4 \times 10 \times \frac{1}{2}$

Scalar product of $\to A$ & $\to B$ = 20

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