A cube is arranged such that its length, breadth and height are along X, Y and Z directions. One of its corners is situated at the origin. Length of each side of the cube is 25 cm. The components of electric field are E x = 400 √ 2 N / C , E y = 0 a n d E z = 0 respectively. Find the flux coming out of the cube at one end. Options: A . &nbsp 25 B . &nbsp 25 √ 2 C . &nbsp 25 √ 2 D . &nbsp z e r o E . &nbsp If assertion is false but reason is true.

Answer: Option C : C Φ x = E x A c o s ( 0 ) = 400 √ 2 × 1 4 × 1 4 = 400 √ 2 16 = 25 √ 2

A cube is arranged such that its length, breadth and height are along X, Y and

Discussion Forum : Electric Charges Fields And Gauss Law

Question -

A cube is arranged such that its length, breadth and height are along X, Y and Z directions. One of its corners is situated at the origin. Length of each side of the cube is 25 cm. The components of electric field are $E_{x} = 400 \sqrt{2} N / C, E_{y} = 0 a n d E_{z} = 0$ respectively. Find the flux coming out of the cube at one end.

Answer: Option C
:
C

Φ_{x} = E_{x} A c o s (0)

= 400 \sqrt{2} \times \frac{1}{4} \times \frac{1}{4}

= \frac{400 \sqrt{2}}{16} = 25 \sqrt{2}

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Discussion Forum : Electric Charges Fields And Gauss Law

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