Discussion Forum : Electric Charges Fields And Gauss Law
Question -
The distance between charges 5×10−11C and −2.7×10−11C is 0.2m. The distance at which a third charge should be placed in order that it will not experience any force along the line joining the two charges is
Answer: Option C
:
C
Was this answer helpful ?
:
C
If two opposite charges are separated by a certain distance, then for it's equalibrium a third
charge should be kept outside and near the charge which is smaller in magnitude.
Here, suppose third charge q is placed at a distance x from −2.7×10−11C then for it's
equalibrium |F1|=|F2| 
⇒ KQ1q(x+0.2)2=KQ2qx2⇒ x=0.556 m
(Here K=14πϵ0 and Q1=5×10−11C, Q2=−2.7×10−11C)
Was this answer helpful ?
Login With Google
Old way of Login
Login With Email
Submit Your Solution hear: