When air is replaced by a dielectric medium of constant k , the maximum force of attraction between two charges separated by a distance Options: A . &nbsp Decreases k times B . &nbsp Remains unchanged C . &nbsp Increases k times D . &nbsp Increases k -1 times

Answer: Option A : A F ′ = 1 4 π ϵ 0 q 1 q 2 r 2 = F K If F is the force in air, then F is less than F since K > 1.

When air is replaced by a dielectric medium of constant k , the maximum force

Question -

When air is replaced by a dielectric medium of constant k , the maximum force of attraction between two charges separated by a distance

Options:

A . Decreases k times

B . Remains unchanged

C . Increases k times

D . Increases k^-1 times

Answer: Option A
:
A

$F^{'} = \frac{1}{4 π ϵ_{0}} \frac{q_{1} q_{2}}{r^{2}} = \frac{F}{K}$
If F is the force in air, then F is less than F since $K > 1.$

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