The impulse response of a system is c(t) = -te-t + 2 e-t (t>0). Its open loop transfer function is Options: A . &nbsp (2s+2)/(s+1)² B . &nbsp (2s+1)/s² C . &nbsp (2s+1)/(s+1)² D . &nbsp (2s+2)/s²

The impulse response of a system is c(t) = -te-t + 2 e-t (t>0). Its open loop tr

Question - The impulse response of a system is c(t) = -te-t + 2 e-t (t>0). Its open loop transfer function is

Options:

A . (2s+2)/(s+1)²

B . (2s+1)/s²

C . (2s+1)/(s+1)²

D . (2s+2)/s²

Answer: Option B

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