Discussion Forum : Pointer
Question -
What will be printed after compiling and running the following code?
main()
{
char *p;
printf("%d %d",sizeof(*p), sizeof(p));
}
main()
{
char *p;
printf("%d %d",sizeof(*p), sizeof(p));
}
Answer: Option B
The sizeof() operator gives the number of bytes taken by its operand. p is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2.
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The sizeof() operator gives the number of bytes taken by its operand. p is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2.
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