Question -
ABC is a right-angled triangle with AB = 6 cm and BC = 8 cm. A circle with center O has been inscribed inside ΔABC. The radius of the circle is
Options:
A .  1 cm
B .  2 cm
C .  3 cm
D .  4 cm
Answer: Option B According to question, Given : AB = 6 cm, BC = 8 cm In right angle ΔABC By using Pythagoras theorem AC2 = AB2 + BC2 AC2 = 62 + 82 AC2 = 36 + 64 AC2 = 100 AC = 10 cm In radius $$\eqalign{ & = \frac{{a + b - c}}{2} \cr & = \frac{{8 + 6 - 10}}{2} \cr & = \frac{4}{2} \cr & = 2\,cm \cr} $$
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