Discussion Forum : True Discount
Question -
An article is listed at Rs.920. A customer pays Rs.742.90 for it after getting two successive discounts. If the rate of first discount is 15%, the rate of 2nd discount is
Answer: Option D
Answer: (d)Total discount= Rs.(920 - 742.90) = Rs.177.10First discount = 15%Discount = 15% of 920= ${920 × 15}/100$ = Rs.138Price after this discount= 920 - 138 = Rs.782Remaining discount= 177.10 - 138 = Rs.39.10Let the second discount be x %.${782 × x}/100 = 39.10$$x = {39.10 × 100}/782$ = 5%Using Rule 3,Here, M.P. = Rs.920, S.P. = Rs.742.90, $D_1 = 15%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$742.90 = 920 $({100 - 15}/100)({100 - D_2}/100)$$7429000/{920 × 85} = 100 - D_2$95 = 100 - $D_2 ⇒ D_2$ = 5%
Was this answer helpful ?
Answer: (d)Total discount= Rs.(920 - 742.90) = Rs.177.10First discount = 15%Discount = 15% of 920= ${920 × 15}/100$ = Rs.138Price after this discount= 920 - 138 = Rs.782Remaining discount= 177.10 - 138 = Rs.39.10Let the second discount be x %.${782 × x}/100 = 39.10$$x = {39.10 × 100}/782$ = 5%Using Rule 3,Here, M.P. = Rs.920, S.P. = Rs.742.90, $D_1 = 15%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$742.90 = 920 $({100 - 15}/100)({100 - D_2}/100)$$7429000/{920 × 85} = 100 - D_2$95 = 100 - $D_2 ⇒ D_2$ = 5%
Was this answer helpful ?
Login With Google
Old way of Login
Login With Email
Submit Your Solution hear: