Discussion Forum : True Discount
Question -
The marked price of a watch is Rs.800. A shopkeeper gives two successive discounts and sells the watch at Rs.612. If the first discount is 10%, the second discount is :
Answer: Option B
Answer: (b)Let the second discount be x%.Then, 90 % of (100 - x) % of 800 = 612$90/100 × {100 - x}/100 × 800 = 612$100 - x = ${612 × 100}/{90 × 8}$ = 85x = 100 - 85 = 15%Using Rule 3,Here, M.P. = Rs.800, S.P. = Rs.612, $D_1 = 10%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$612 = 800 × $({100 - 10}/100) × ({100 - D_2}/100)$612 = $800 × 90/100 × {100 - D_2}/100$$6120/72 = 100 - D_2$$D_2 = {100 - 6120}/72$= ${7200 - 6120}/72$ = 15%
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Answer: (b)Let the second discount be x%.Then, 90 % of (100 - x) % of 800 = 612$90/100 × {100 - x}/100 × 800 = 612$100 - x = ${612 × 100}/{90 × 8}$ = 85x = 100 - 85 = 15%Using Rule 3,Here, M.P. = Rs.800, S.P. = Rs.612, $D_1 = 10%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$612 = 800 × $({100 - 10}/100) × ({100 - D_2}/100)$612 = $800 × 90/100 × {100 - D_2}/100$$6120/72 = 100 - D_2$$D_2 = {100 - 6120}/72$= ${7200 - 6120}/72$ = 15%
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