Discussion Forum : Introduction To Methods And Streams
Question -
class test {
int a;
int b;
void meth(int i , int j) {
i *= 2;
j /= 2;
}
}
class Output {
public static void main(String args[])
{
test obj = new test();
int a = 10;
int b = 20;
obj.meth(a , b);
System.out.println(a + " " + b);
}
}
What is the output of this program?
class test {
int a;
int b;
void meth(int i , int j) {
i *= 2;
j /= 2;
}
}
class Output {
public static void main(String args[])
{
test obj = new test();
int a = 10;
int b = 20;
obj.meth(a , b);
System.out.println(a + " " + b);
}
}
Answer: Option A
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Variables a & b are passed by value, copy of their values are made on formal parameters of
function meth() that is i & j. Therefore changes done on i & j are not reflected back on original
arguments. a & b remain 10 & 20 respectively.
output:
$ javac Output.java
$ java Output
10 20
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