Discussion Forum : Physics
Question -

What is the refractive index of a prism whose angle  A = `60^circ` and angle of minimum deviation `d_m = 30^circ`?

Options:
A .  `sqrt(2)`
B .  `1/sqrt(2)`
C .  1
D .  `1/sqrt(3)`
Answer: Option A

Refractive index of prism

            `mu = (sin((A + delta_m)/(2)))/(sin( A/2))`

                   =`( sin( (60^circ + 30^circ)/(2)))/(sin((60^circ)/(2)))`

                   = `(sin 45^circ)/(sin 30^circ)`

                   = `(1/sqrt(2))/(1/2)`

                   = `1/sqrt(2) xx 2/1`

                   =` sqrt(2)`




Was this answer helpful ?
Next Question
Submit Your Solution hear:

Your email address will not be published. Required fields are marked *