X-rays of wavelength&n

Question -

X-rays of wavelength 0.14 nm are scattered from a block of carbon . What will be the wavelength of X-rays scattered at `90^circ` ?

Options:

A . 0.140 nm

B . 0.142 nm

C . 0.144 nm

D . 0.146 nm

Answer: Option B

For `phi` = `90^circ`, cos `phi` = 0

So, `lambda` = `lambda +( h)/(m_e c)`

=` 0.140 xx 10^-9 + (6.63 xx 10^-34)/((9.1 xx 10^-31)(3 xx 10^8))`

= `(0.140 xx 10^-9 + 2.4 xx 10^-12)`m

= 0.142 nm.

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