Discussion Forum : Physics
Question -
The distance time graph of a particle at time t makes angle `45^circ` with respect to time axis . After one second , it makes angle `60^circ` with respect to time axis. what is the acceleration of the particle ?
Answer: Option A
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The slop of distance -time graph gives speed.
The change in velocity in one second = tan `60^circ - tan 45 ^circ` = `sqrt(3) - 1`
`:.` acceleration = `(Delta v) /(Delta t) = (sqrt(3) - 1)/(1)`
= `sqrt(3) - 1`unit.
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