A particle starts with a velocity of 2 m/s and moves in a straight line with a retardation of 0.1 `m/s^2`. the time that it takes to describe 15 m is :
Sol. Le the particle returns back after time t = `t_0`
For this , v = 0, at t = `t_0`
v = u + a
or 0 = 2 - 0.1`t_0`
`t_0 = 2/0.1 = 20` sec.
s = ut + `1/2 at^2`
or ` 15 = 2 - 1/2 0.1t^2`
or `30 = 4t - 0.1t^2`
or `300 = 40t - t^2`
or `t^2 - 40 t + 300 = 0`
`:.` t = `(40 pm sqrt(1600 - 1200))/(2 xx 1)`
= `(40 pm 20)/(2 )`
`:.` t = 30 sec or 10 sec.
Hence , (d) is correct .
Submit Your Solution hear: