Discussion Forum : Physics
Question -
A particle is projected veritically upward in vacuum with a speed 40 m/s then velocity of particle when it reaches at maximum height 2 s before, is (Take g = 10 m/`s^2`)
Answer: Option A
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At the maximum height , `v = 0`
`:.` v = u - gt
0 = u - g`t_0`
`:.` ` t_0 = u/g = 40/10 = 4 sec`
`:.` v = u - gt
= 40 - 10(4 - 2) = 20 m/s
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