Discussion Forum : Physics
Question -
Two particles are projected vertically upwards with the same velocity on two different planets with accelerations due to gravities `g_1 and g_2` respectively . If they fall back to heir initial points of projection after lapse of time `t_1 and t_2` respectively . Then
Answer: Option B
Was this answer helpful ?
In the absence of air ,
t = time of flight
= 3 x time of ascent
= `2 xx u/g = (2u)/(g)`
`:.` `t_1 = (2u)/(g_1)` ....................(i)
and `t_2 = (2u)/(g_2)` ......................(ii)
Now from eq. (i) and (ii)
`:.` `t_1 g_1 = t_2 g_2`
Was this answer helpful ?
Login With Google
Old way of Login
Login With Email
Submit Your Solution hear: