A body of mass 10 kg is to be raised by a massless string from rest to rest , through a height 9.8 m.The greatest tension which he string can safely bear is 20 kg wt. The least time of ascent is
`a_max = (T - mg)/(m) =( (20 - 10)g)/(10) = g`
During half time , body is accelerated from rest and during next half time decelerates with same magnitude to come to rest.
`:.` `h/2 = 1/2 a_max t_1^2`
`:.` `t_1 = sqrt(h/a_max)` = 1 sec.
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