A stone of mass 0.3 kg attached to a 1.5 m long string is whirled around in a horizontal circle at a speed of 6 m/s. The tension in the string is
The force of tension in the string provides required centripetal force to keep the stone in circular motion .
`:.` `T = (mv^2)/(R)`
= `(0.3 xx (6)^2)/(1.5)`
= 7.2 N.
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