A particle move with a velocity `(5 hat(i) - 3 hat(j) + 6 hat (k))` m/s under the influence of a constant force
`vec(F) = 10 hat(i) + 10 hat(j) + 20 hat(k)`. The instantaneous power applied to the particle is
`because vec(v) = (5 hat(i) - 3hat(j) + 6 hat(k)` m/s
`vec (F) = 10 hat(i) + 10 hat(j) + 20 hat(k)`
`:.` power =` vec(F) * vec (v)`
= `(10hat(i) + 10 hat (j) + 20 hat (k)) * (5hat(i) - 3hat(j) + 6 hat(k))`
= 50 - 30 + 120 = 140 joule / sec
Submit Your Solution hear: