The coefficient of earth pressure for active state of plastic equilibrium is given by ___________ Options: A . &nbsp\(K_a=\frac{1}{tan^2 (45°+\frac{φ}{2})} \) B . &nbsp\(K_a=tan^2 (45°+\frac{φ}{2}) \) C . &nbsp\(K_a=sin^2 (45°+\frac{φ}{2}) \) D . &nbsp\(K_a=\frac{1}{cot^2 (45°+\frac{φ}{2})} \)

The coefficient of earth pressure for active state of plastic equilibrium is giv

Question - The coefficient of earth pressure for active state of plastic equilibrium is given by ___________

Options:

A . \(K_a=\frac{1}{tan^2 (45°+\frac{φ}{2})} \)

B . \(K_a=tan^2 (45°+\frac{φ}{2}) \)

C . \(K_a=sin^2 (45°+\frac{φ}{2}) \)

D . \(K_a=\frac{1}{cot^2 (45°+\frac{φ}{2})} \)

Answer: Option A
Answer: (a).\(K_a=\frac{1}{tan^2 (45°+\frac{φ}{2})} \)

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