What will be the output of the program?
When the fix() method is first entered, start()'s s1 and fix()'s s1 reference variables both
refer to the same String object (with a value of "slip"). Fix()'s s1 is reassigned to a new
object that is created when the concatenation occurs (this second String object has a
value of "slipstream"). When the program returns to start(), another String object is created,
referred to by s2 and with a value of "stream".
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