int f1(int a, int b) { return ( f2(20) ); } int f2(int a) { return (a*a); }
Options:
A .  Yes
B .  No
Answer: Option A
Yes, It will return the value 20*20 = 400 Example:
#include<stdio.h> int f1(int, int); /* Function prototype */ int f2(int); /* Function prototype */ int main() { int a = 2, b = 3, c; c = f1(a, b); printf("c = %d\n", c); return 0; } int f1(int a, int b) { return ( f2(20) ); } int f2(int a) { return (a * a); }
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