Question - A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of ∠AOP is 60∘. Find the value of x.
Options:
A .  30∘
B .  40∘
C .  50∘
D .   60∘
Answer: Option A : A ∠AOP+∠AON=90∘ (as ON is perpendicular to POQ) Given, ∠AOP=60∘ ⟹∠AON=90∘−60∘ ∠AON=30∘ By Laws of reflection, ∠AON=∠BON=x Thus, x=30∘
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