Question -One root of the following given equation 2x5−14x4+31x3−64x2+19x+130=0 is
Options:
A .  1
B .  3
C .  5
D .  7
Answer: Option C : C We can solve this problem using options given - On putting x = 5, we get 2(5)5−14(5)4+31(5)3−64(5)2+19(5)+130=0 Hence x = 5 satisfies the given equation. Thus 5 is a root of the equation. Other options will not satisfy the given equation so the answer is x = 5.
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