Question -
If the equation 9x2+6kx+4=0 has equal roots, then find the value of k =
Options:
A .  0
B .  2 , 0
C .  -2, 0
D .  ± 2
Answer: Option D : D Given, the roots of quadratic equation 9x2+6kx+4=0are real and equal. Discriminant,Δ=b2−4acΔ=36k2–4(4)(9)=36k2–4(36) The roots of quadratic equation are real and equal thenΔ=036k2–4(36)=0k2−4=0k2=4k=√4∴k=±2
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