Question -
In a reaction A+2B⇋2C;2molesofA,3 mole of Band2moleofC are placed in a 2 L flask and the equilibrium concentration of Cis0.5mole/L. The equilibrium constant K for the reaction is:
Options:
A .  0.073
B .  0.147
C .  0.05
D .  0.026
Answer: Option C : C A+2B⇋2CInitialmoles232Molarconc.2/2=1mol/L3/2=1.5mol/L2/2=1mol/LAtEqui.Conc1+0.25=1.25mol/L1.5+0.5=2mol/L0.5mol/L K=(0.5)2/(1.25×(2)2)=0.05 Note that concentration of C has decreased, i.e., to attain equilibrium, reaction has shifted backwards. Decrease in conc. of C will be 0.5mol/L and hence increase in concentration of B will be 0.5mol/L and that of A will be 0.25mol/L
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