Question -
A solution has a 1:4 mole ratio of pentane to hexane. The vapour pressure of the pure hydrocarbons at 20∘ is 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in the vapour phase would be
Options:
A .  0.549
B .  0.200
C .  0.786
D .  0.478
Answer: Option D : D Mole fractionof pentane invapourphase = Y1=P1P1+P2=P01X1P01X1+P02X2 =440×15440×15+120×15=0.478
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