Question -
A 0.001 molal solution of [Pt(NH3)4cl4] in water had a freezing point depression of 0.0054∘. If Kf for water is 1.80, the correct formulation for the above molecule is
Options:
A .  [Pt(NH3)4Cl3]Cl
B .  [Pt(NH3)4]Cl4
C .  [Pt(NH3)4Cl2]Cl3
D .  [Pt(NH3)4Cl2]Cl2
Answer: Option D : D △T=iKfm ⇒i=△TfKfm=0.00541.80×0.001=3 Thus complexproducesthreeionspermolecule.hence possiblecorrectformulais [Pt(NH3)4Cl2]Cl2
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