Question -
Question 11-12 is based on the following given information: Assume a hypothetical cubic crystal lattice, named JEE-centered cubic (jcc) with the following characteristics: I. An atom is present at all the corners of the cube II. An atom is present at the center of two pairs of opposite faces III. An atom is present at the center of all the edges of the cube IV. One atom is present at its body-center How many atoms are effectively present per unit cell in this hypothetical crystal lattice?
Options:
A .  8
B .  7
C .  6
D .  5
Answer: Option B : B I. 8 corner atom ×(18) atom per unit cell = 1 atom II. 4 face-centered atoms ×(12)atom per unit cell = 2 atom III. 12 edge-centered atoms ×(14) atom per unit cell = 3 atom IV. 1 body centered atom ×1 atom per unit cell = 1 atom So, Total number of atoms per unit cell =1+2+3+1=7atoms
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