Question -
For one mole of a van der Waal's gas when b =o and T = 300 K, the PV vs 1V plot is shown below. The value of the Van der Waal's constant "a" (atmL2mol−2) is
Options:
A .  1.0
B .  4.5
C .  1.5
D .  3.0
Answer: Option C : C ⟮P+aV2⟯⟮V⟯=RT PV + aV = RT y = RT –a(V) y = RT –a(x) So, slope = a = 21.6–20.13−2=1.51=1.5
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