Discussion Forum : States Of Matter
Question - n1 and n2  moles of two ideal gases (mol. wt. M1  and M2) respectively at temperature T1K and T2K are mixed.  Assuming that no loss of energy, the temperature of mixture becomes -
Options:
A .  n1T1+n2T2
B .  n1T1+n2T2T1+T2 
C .  n1T1+n2T2n1+n2 
D .  n1×T2n1×n2
Answer: Option C
:
C
Let the final temperature be T , then K E1 + K Emixture
32 n1RT1 +32n2RT2 =32 (n1+n2) RT
T = n1T1+n2T2n1+n2

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