Question -2VO+3Fe2O3→6FeO+V2O5 If we start with 2g of VO and 5.75g of Fe2O3, which is the limiting reagent? [V = 47.87g] [Fe = 55.85g]
Options:
A .  VO
B .  Fe2O3
C .  Fe2O
D .  V2O5
Answer: Option B : B If you check, the reaction is already balanced 2 moles of VO = 3 moles of Fe2O3 2×(47.87+16)=3×(2×55.85+3×16) 2(63.87)g=3×(159.7)g 127.74g of VO = 478.1g of Fe2O3 ∴2g of VO = 2×478.1127.74=7.50g of Fe2O3 But only 5.75g of Fe2O3 is present. This Fe2O3 will get used up in the reaction and is the limiting reagent.
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