Question -
The enthalpies for the following reactions at 25°C are given. 12H2(g)+12O2(g)→OH(g);△H=10.06Kcal H2(g)→2H(g);△H=104.18Kcal O2(g)→2O(g);△H=118.32Kcal Calculate the OH bond energy in the O - H group
Options:
A .  100.19 K col
B .  101.19 K col
C .  -101.19 K col
D .  -100.19 K col
Answer: Option C : C H(g) + O(g) → O - H(g) Required equation Given: 12H2(g)+12O2(g)→OH(g);△H=+10.06Kcal H(g)→12H2(g);△H=−52.09Kcal O(g)→12O2(g);△H=−59.16Kcal Adding them we get H(g)+O(g)+(OH)(g)△H=−101.19Kcal
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