Question -
In a process a system does 140 J of work on the surrondings and only 40 J of heat is added to the system, hence change in internal energy is
Options:
A .  180 J
B .  -180 J
C .  -23.92 Cal
D .  -180 J
Answer: Option C : C Given W=−140J;q=405 ΔE=q+W=40−140=−100J(1cal=4.18J)=−23.92Cal
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