Question -
The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25∘C are −400kJ/mol, −300kJ/mol and −1300kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25∘C is
Options:
A .  + 2900 kJ
B .  −2900 kJ
C .  −16.11 kJ
D .  +16.11 kJ
Answer: Option C : C The standard enthalpy of the combustion of glucose can be calculated by the equ. C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l) ΔHc=6×ΔHf(CO2)+6×ΔHf(H2O)−ΔHf[C6H12O6] ΔH0=−2900180=−16.11kJ/gm
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